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stad
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« on: March 28, 2012, 12:51:30 am » |
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The idea in T6 to have an upgrade of a slot suitable for all classes is great. Just one question about this: Is there a possibility to have an item that upgrades your slot item with 1 level. Example : you have a full suit of T5 but miss a cloak and shoulders (  ) So is it possible to use your armor upgrade item of T6 to improve your cloak from T4 to T5 with an armor upgrade of T6? |
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Natedog
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« Reply #1 on: March 28, 2012, 02:32:50 am » |
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T5 Cloak / Shoulders should be much easier to get now. Omadon // Death Knight have had their spawn rate upped to 10% so you shouldn't have a hard time farming them now. I came back and did a few runs of it and got my tanks their T5 accessories.
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Hunter
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« Reply #2 on: March 28, 2012, 01:27:59 pm » |
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Its possible, but would require a LOT of time making up new recipes for each of the new combines. Also we want players to do the tiers in order without skipping, kinda the theme on EZ.
Yes those 2 mobs had 1% chance upped to 10% chance so there is about a 50% chance of getting 1 of those 2 bosses each time clearing the zone, so it shouldn't be too bad now.
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Hunter - EZ Server GM
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Gyan1010
Newbie
Posts: 36
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« Reply #3 on: March 28, 2012, 06:48:25 pm » |
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been curious how many mobs actually have a chance to spawn them. I'm not t5 yet but know that most people do probability incorrectly. Just to make sure you are correct you would need 7 possible chances at 10% per chance to have a > 50% chance of one spawning. If there are only 5, like some might calculate to be 50%, then that is actually only a 40.95% chance.
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Hunter
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« Reply #4 on: March 28, 2012, 09:47:00 pm » |
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There are 5 trash mobs at 10% chance each kill to spawn 1 of 2 of those bosses.
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Hunter - EZ Server GM
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Gyan1010
Newbie
Posts: 36
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« Reply #5 on: March 29, 2012, 06:37:06 am » |
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Ah then if the the chances of spawning a specific boss at least once are
1 - (0.9^5) = .40951 = 40.951%
And chances of spawning either boss at least once depend on if the calculation is done in the same roll.
If its like rand 100 where 1-10 = boss 1 and 11-20 = boss 2 then the chances are
1 - (0.8^5) = .67232 = 67.232%
If it is 2 separate rolls each with a 10% chance then chances of either boss is
1 - (0.9^10) = .65132 = 65.132%
Doesn't really bother me either way just figured the math should be right.
When dealing with multiple trials you either have to calculate the % of getting only 1 at any spawn, adding in chance to get only 2 and the different ways that can happen, etc, or you can just do 1 calculation on the chance that you get no spawns and then subtracting that from 1.
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Hunter
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« Reply #6 on: March 29, 2012, 06:40:26 am » |
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When mob dies, there is 10% chance of a boss.
If a boss spawns, then it will be randomly 1 of 2 bosses.
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Hunter - EZ Server GM
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Xiggie | Stone
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« Reply #7 on: March 29, 2012, 08:41:21 am » |
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Ah then if the the chances of spawning a specific boss at least once are
1 - (0.9^5) = .40951 = 40.951%
And chances of spawning either boss at least once depend on if the calculation is done in the same roll.
If its like rand 100 where 1-10 = boss 1 and 11-20 = boss 2 then the chances are
1 - (0.8^5) = .67232 = 67.232%
If it is 2 separate rolls each with a 10% chance then chances of either boss is
1 - (0.9^10) = .65132 = 65.132%
Doesn't really bother me either way just figured the math should be right.
When dealing with multiple trials you either have to calculate the % of getting only 1 at any spawn, adding in chance to get only 2 and the different ways that can happen, etc, or you can just do 1 calculation on the chance that you get no spawns and then subtracting that from 1.
Has anyone really been far even as decided to use even go want to do look more like? |
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Gyan1010
Newbie
Posts: 36
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« Reply #8 on: March 29, 2012, 08:51:50 am » |
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Has anyone really been far even as decided to use even go want to do look more like?
Dear lord man, how would you diagram that sentence? Lay off the ale monk man  |
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Gyan1010
Newbie
Posts: 36
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« Reply #9 on: March 29, 2012, 09:00:43 am » |
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When mob dies, there is 10% chance of a boss.
If a boss spawns, then it will be randomly 1 of 2 bosses.
Anyway its actually worse that way than in my other post. It means a 40.951% of either boss spawning at least once. But only half that, 20.476% chance for a specific one. |
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Xiggie | Stone
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« Reply #10 on: March 29, 2012, 09:02:01 am » |
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The point is that makes as much sense as what you said. 5 mobs, each having 10% chance to spawn a boss averages out to 50% over a given period of time.
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Gyan1010
Newbie
Posts: 36
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« Reply #11 on: March 29, 2012, 09:17:55 am » |
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The point is that makes as much sense as what you said. 5 mobs, each having 10% chance to spawn a boss averages out to 50% over a given period of time.
Wrong you multiply percentage. Like a coin toss. Toss it once and you have 2 outcomes. 50% heads, 50% tails. Toss it twice and you 4 outcomes. 25% chance of 2 heads, 25% chance of 2 tails, and a 50% chance of 1 of each. You need to take each outcome into the percentage. Since order doesn't matter the 1 of each happens twice doubling the percentage over 2 heads or tails. If you are working toward at least 1 spawn of a boss then you need to account for each way that can happen, OR the 1 way in which it cannot happen (usually easier). Therefore you multiply the chance of not spawning them for 5 times. 90% * 90% * 90% * 90% * 90% = 59.049% chance of not spawning. Which stands to reason there is a 40.951% chance that you will spawn at least 1. |
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Xiggie | Stone
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« Reply #12 on: March 29, 2012, 09:44:29 am » |
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Using that logic and applying it to the coin toss 5 times over you only have a 31.25% chance of getting heads and a 31.25% chance of getting tails. Common sense dictates that is not the case because there is a missing 37.5%. You are over complexing. 5 spawns, 10% chance on each spawn over a given period of time will average out to 50% spawn rate on a full clear of all 5 mobs. If there were 10 mobs at 10% chance each, on average you should get one per clear.
Additionally using your math to figure spawn chance instead of not spawn chance gives you a .00100% chance to spawn the bosses per clear.
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Gyan1010
Newbie
Posts: 36
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« Reply #13 on: March 29, 2012, 10:06:35 am » |
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Your doing it wrong, let me give you a visual of the coin toss. 5 tosses 32 outcomes ------------
HHHHH
HHHHT
HHHTH
HHHTT
HHTHH
HHTHT
HHTTH
HHTTT | ------------
HTHHH
HTHHT
HTHTH
HTHTT
HTTHH
HTTHT
HTTTH
HTTTT | ------------
THHHH
THHHT
THHTH
THHTT
THTHH
THTHT
THTTH
THTTT | ------------
TTHHH
TTHHT
TTHTH
TTHTT
TTTHH
TTTHT
TTTTH
TTTTT
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the only time you don't get a heads is if its all tails. To find the chance for a heads toss, my math would have you take the chance to get tails 50% or .5, multiply it 5 times over. 0.5 * 0.5 * 0.5 * 0.5 * 0.5 = .03125 = 3.125% chance to get tails EVERY toss. Which is also 1/32 which makes sense because it happens only once in the 32 different outcomes. Therefore the chance to get 1 OR MORE heads in 5 tosses is 100% - 3.125% = 96.875% |
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Xiggie | Stone
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« Reply #14 on: March 29, 2012, 10:24:20 am » |
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Using that math you are figuring if there was a spawn 5 out of 5 times which would be the 10%*10%*10%*10%*10=.00100%. When figuring the % chance to spawn 1 time out of the 5 possible you do 10%*5=50%.
Don't take my word for it though. Head to ldons. There is a 10% chance for mobs to drop a 10 point token. On average 1 out of every 1 will drop a token. Kill a few hundred of them and you will find out that within reason it adds up to being 10% chance to drop per 1 and 100% chance on 10 mobs.
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